For a sparingly soluble salt AB, the relationship of its solubility product () with its solubility ( — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The dissociation reaction is $\text{A}_p\text{B}_q \rightleftharpoons p\text{A}^{q+} + q\text{B}^{p-}$. For a molar solubility of $S$, the ion concentrations are $[\text{A}^{q+}] = pS$ and $[\text{B}^{p-}] = qS$. The solubility product is $L_s = (pS)^p(qS)^q = p^p q^q S^{p+q}$.