The solubility of AX is . Its solubility product is — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The dissociation is $\text{A}_2\text{X}_3 \rightleftharpoons 2\text{A}^{3+} + 3\text{X}^{2-}$. With a solubility of $y$, $[\text{A}^{3+}] = 2y$ and $[\text{X}^{2-}] = 3y$. The solubility product is $K_{sp} = [\text{A}^{3+}]^2[\text{X}^{2-}]^3 = (2y)^2(3y)^3 = 4y^2 \cdot 27y^3 = 108y^5$.