If ionization of XY takes place then, number of Y ions will be equal to — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The dissociation reaction is $\text{X}_a\text{Y}_b \rightleftharpoons a\text{X}^{+b} + b\text{Y}^{-a}$. By stoichiometry, for every 1 formula unit dissolved, $a$ moles of $\text{X}^{+b}$ and $b$ moles of $\text{Y}^{-a}$ are produced. Therefore, the concentration of $\text{Y}^{-a}$ relates to $\text{X}^{+b}$ by the stoichiometric ratio: $[\text{Y}^{-a}] = \frac{b}{a} [\text{X}^{+b}]$.