The pH value of 0.1 M solutions of (I), (II), (III), NaOH (IV) and HCl (V) is in the order — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

V (HCl) is a strong acid, yielding the lowest pH. II ($\text{CH}_3\text{COOH}$) is a weak acid. III ($\text{CH}_3\text{COONH}_4$) is a neutral salt ($\text{pH} = 7$) because $K_a = K_b$. I ($\text{CH}_3\text{COONa}$) is a basic salt resulting from anionic hydrolysis ($\text{pH} > 7$). IV (NaOH) is a strong base, yielding the highest pH. The increasing order is V < II < III < I < IV.