How much water must added to 300 ml of solution of for the degree of dissociation of the acid to dou — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

According to Ostwald's dilution law, the degree of dissociation $\alpha \approx \sqrt{\frac{K_a}{C}} \propto \sqrt{V}$. To double the degree of dissociation ($\alpha \to 2\alpha$), the final volume must become 4 times the initial volume. Thus, $V_{final} = 4 \times 300\text{ ml} = 1200\text{ ml}$. The amount of water to be added is $V_{final} - V_{initial} = 1200\text{ ml} - 300\text{ ml} = 900\text{ ml}$.