For weak electrolyte, AB, the degree of ionization would be () — Ionic Equilibrium Chemistry Question
Question
For weak electrolyte, AB, the degree of ionization would be ($V = \text{volume of solution having 1 mole of electrolyte and } K \text{ is the ionization constant of the electrolyte}$)
Answer: D
💡 Solution & Explanation
According to Ostwald's dilution law for a weak electrolyte, the degree of ionization is $\alpha = \sqrt{\frac{K}{C}}$. The concentration $C$ is defined as moles/volume. Since there is exactly 1 mole of the electrolyte, $C = \frac{1}{V}$. Substituting this into the formula gives $\alpha = \sqrt{K \cdot V}$.
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