Ionic EquilibriummediumMCQ SINGLE

The dissociation constant of acetic acid is 0.000018 and that for cyanoacetic acid is 0.0036 at 298 Ionic Equilibrium Chemistry Question

Question

The dissociation constant of acetic acid is 0.000018 and that for cyanoacetic acid is 0.0036 at 298 K. What would be the ratio of volumes of the two acid solutions, each containing equal moles of the acids, so that the solutions becomes isohydric?

Answer: C

💡 Solution & Explanation

Isohydric solutions have the same $[\text{H}^+]$. For weak acids, $[\text{H}^+] \approx \sqrt{K_a C}$. Thus, $K_{a1}C_1 = K_{a2}C_2$. Since both contain equal moles ($n$), $C = n/V$, making $K_{a1}/V_1 = K_{a2}/V_2$. The volume ratio is $V_1/V_2 = K_{a1}/K_{a2} = 0.000018 / 0.0036 = 18 / 3600 = 1/200$.

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