What is the pH of solution made by mixing equal volumes of , , ? — Ionic Equilibrium Chemistry Question
Question
What is the pH of solution made by mixing equal volumes of $0.1\text{ N} – \text{H}_2\text{SO}_4$, $0.1\text{ N} – \text{HNO}_3$, $0.1\text{ N} – \text{HCl}$?
💡 Solution & Explanation
All three components are strong acids, and they are provided with identical normalities ($0.1\text{ N}$). Normality directly reflects the concentration of available $\text{H}^+$ equivalents. Mixing equal volumes of solutions that all have an $\text{H}^+$ concentration of $0.1\text{ N}$ yields a final mixture with the exact same normality, $0.1\text{ N}$ (or $0.1\text{ M}$ in terms of $\text{H}^+$). The $\text{pH} = -\log(0.1) = 1$.