The pH of solution is () — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

NaOH is a strong base and dissociates completely, so $[\text{OH}^-] = 0.005\text{ M} = 5 \times 10^{-3}\text{ M}$. The pOH is $-\log(5 \times 10^{-3}) = 3 - \log 5$. Since $\log 5 = 1 - \log 2 = 1 - 0.3 = 0.7$, the pOH is $3 - 0.7 = 2.3$. The pH is $14 - \text{pOH} = 14 - 2.3 = 11.7$.