The ionic product of water is at 25°C. Assuming the density of water independent from change in temp — Ionic Equilibrium Chemistry Question
Question
The ionic product of water is $1.0 \times 10^{-14}$ at 25°C. Assuming the density of water independent from change in temperature, the ionic product of water at 50°C will be
Answer: C
💡 Solution & Explanation
The self-ionization of water is an endothermic process. As the temperature increases from 25°C to 50°C, the equilibrium shifts forward, which increases the ionic product ($K_w$). Therefore, $K_w$ must be greater than $1.0 \times 10^{-14}$. Among the given options, only $5.9 \times 10^{-14}$ represents a biologically and chemically realistic increase in $K_w$ for this temperature shift.
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