The degree of dissociation of water at 25°C is and density is . The ionic constant for water is — Ionic Equilibrium Chemistry Question
Question
The degree of dissociation of water at 25°C is $1.8 \times 10^{-7}\%$ and density is $1.0\text{ g cm}^{-3}$. The ionic constant for water is
Answer: A
💡 Solution & Explanation
The density of water is $1.0\text{ g/ml} = 1000\text{ g/L}$. Molarity of water $C = 1000 / 18 = 55.55\text{ M}$. The degree of dissociation $\alpha = 1.8 \times 10^{-7}\% = 1.8 \times 10^{-9}$. The concentration of hydrogen ions $[\text{H}^+] = C\alpha = 55.55 \times 1.8 \times 10^{-9} \approx 1.0 \times 10^{-7}\text{ M}$. The ionic constant $K_w = [\text{H}^+][\text{OH}^-] = (10^{-7})(10^{-7}) = 1.0 \times 10^{-14}$.
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