Match the column — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

(A) NaCl is a salt of a strong acid and strong base. It undergoes no hydrolysis, so pH = 7.0. Matches Right C. (B) $\text{Na}_2\text{CO}_3$ is a salt of a strong base and weak acid. It undergoes anionic hydrolysis to form an alkaline solution (pH > 7.0). Matches Right B and E. (C) $\text{NH}_4\text{Cl}$ is a salt of a weak base and strong acid. It undergoes cationic hydrolysis to form an acidic solution (pH < 7.0). Matches Right A and D. (D) $\text{CH}_3\text{COONH}_4$ is a salt of a weak acid and weak base. It undergoes both cationic and anionic hydrolysis. Since $K_a(\text{CH}_3\text{COOH}) = K_b(\text{NH}_4\text{OH}) = 1.8 \times 10^{-5}$, the solution is precisely neutral with pH = 7.0 at $25^\circ\text{C}$. Matches Right A, B, and C. Therefore, correct answer is 1-C; 2-B,E; 3-A,D; 4-A,B,C.