Solid ammonium carbamate dissociates as: NH₂COONH₄(s) ⇌ 2NH₃(g) + CO₂(g). In a closed vessel solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium ammonia is added

Question

Solid ammonium carbamate dissociates as: NH₂COONH₄(s) ⇌ 2NH₃(g) + CO₂(g). In a closed vessel solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium ammonia is added such that the partial pressure of NH₃ at new equilibrium now equals the original total pressure. The ratio of total pressure at new equilibrium to that of original total pressure is

Prashant Kotian · Accepted Answer

Correct answer: C. Let initial eq pressures be P_CO₂ = p, P_NH₃ = 2p. Original total pressure P₁ = 3p. K_p = (2p)²(p) = 4p³. NH₃ is added so new P_NH₃' = P₁ = 3p. K_p remains constant: (3p)² × P_CO₂' = 4p³, which gives P_CO₂' = 4p/9. New total pressure P₂ = 3p + 4p/9 = 31p/9. Ratio P₂/P₁ = (31p/9) / 3p = 31 / 27. Therefore, correct answer is C.

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