Carbon monoxide in water gas, reacts with steam according to the reaction:<br>CO(g) + H₂O(g) ⇌ CO₂(g — Chemical Equilibrium Chemistry Question
Question
Carbon monoxide in water gas, reacts with steam according to the reaction:<br>CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g); K_eq = 0.3333<br>If two volumes of water gas (containing 1:1 of CO and H₂) are mixed with five volumes of steam, then the volume ratio of the four gases present at equilibrium is
💡 Solution & Explanation
Initial moles: CO = 1, H₂ = 1, H₂O = 5, CO₂ = 0. Change: CO = 1-x, H₂O = 5-x, CO₂ = x, H₂ = 1+x. K_eq = [x(1+x)] / [(1-x)(5-x)] = 1/3. 3x + 3x² = 5 - 6x + x² => 2x² + 9x - 5 = 0. Solving gives x = 0.5. Eq moles: CO = 0.5, H₂O = 4.5, CO₂ = 0.5, H₂ = 1.5. The ratio CO : H₂O : CO₂ : H₂ = 0.5 : 4.5 : 0.5 : 1.5 = 1 : 9 : 1 : 3. Therefore, correct answer is D.