PCl₅ (molecular mass = M) dissociates into PCl₃ and Cl₂ as: PCl₅(g) ⇌ PCl₃(g) + Cl₂(g). If the total pressure of the system at equilibrium is P and the density is 'd' at temperature, T K. The degree o

Question

PCl₅ (molecular mass = M) dissociates into PCl₃ and Cl₂ as: PCl₅(g) ⇌ PCl₃(g) + Cl₂(g). If the total pressure of the system at equilibrium is P and the density is 'd' at temperature, T K. The degree of dissociation of PCl₅ may be represented as

Prashant Kotian · Accepted Answer

Correct answer: B. The average molar mass of the equilibrium mixture is M_avg = dRT / P. For the dissociation of PCl₅, the degree of dissociation α is related to molar masses by α = (M_theoretical - M_avg) / M_avg = M / M_avg - 1. Substituting M_avg gives α = M / (dRT / P) - 1 = PM / dRT - 1. Therefore, correct answer is B.

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