When α-D-glucose is dissolved in water, it undergoes a partial conversion to β-D-glucose. This conversion, called mutarotation, stops when 64.0% of the glucose is in the β-form. Assuming that equilibr

Question

When α-D-glucose is dissolved in water, it undergoes a partial conversion to β-D-glucose. This conversion, called mutarotation, stops when 64.0% of the glucose is in the β-form. Assuming that equilibrium has been attained, what is ΔG° for the reaction: α-D-glucose ⇌ β-D-glucose, at this experimental temperature?

Prashant Kotian · Accepted Answer

Correct answer: C. At equilibrium, % of β-form = 64%, so % of α-form = 36%. K = [β] / [α] = 64 / 36 = 16 / 9 ≈ 1.78. Using the relation ΔG° = -RT ln K, we get ΔG° = -RT log_e(1.78). Therefore, correct answer is C.

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