Steam decomposes at high temperature according to the equation:
2H₂O(g) ⇌ 2H₂(g) + O₂(g); ΔH° = 240 kJ/mole and ΔS° = 50 JK⁻¹/mole
The temperature at which the equilibrium constant (K_p°) become

Question

Steam decomposes at high temperature according to the equation:
2H₂O(g) ⇌ 2H₂(g) + O₂(g); ΔH° = 240 kJ/mole and ΔS° = 50 JK⁻¹/mole
The temperature at which the equilibrium constant (K_p°) becomes 1.0, is

Prashant Kotian · Accepted Answer

Correct answer: B. When K_p° = 1.0, ΔG° = -RT ln(1.0) = 0. We know ΔG° = ΔH° - TΔS°. Setting ΔG° to 0 gives T = ΔH° / ΔS° = (240 × 10³ J/mol) / (50 J K⁻¹ mol⁻¹) = 4800 K. Therefore, correct answer is B.

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