For a reversible reaction: A ⇌ B (with forward rate constant K₁ and backward K₂), the initial molar concentration of A and B are a M and b M, respectively. If x M of A is reacted till the achievement

Question

For a reversible reaction: A ⇌ B (with forward rate constant K₁ and backward K₂), the initial molar concentration of A and B are a M and b M, respectively. If x M of A is reacted till the achievement of equilibrium, then x is

Prashant Kotian · Accepted Answer

Correct answer: A. At equilibrium, the rates of forward and backward reactions are equal. Rate_forward = K₁[A] = K₁(a - x). Rate_backward = K₂[B] = K₂(b + x). Equating them: K₁(a - x) = K₂(b + x) => K₁a - K₁x = K₂b + K₂x. Rearranging gives x(K₁ + K₂) = K₁a - K₂b. Thus, x = (K₁a - K₂b) / (K₁ + K₂). Therefore, correct answer is A.

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