Solid NH₄HS dissociates into NH₃ and H₂S at a certain temperature, the equilibrium pressure is P atm. If now, NH₃ is pumped into the system so that its partial pressure becomes P atm, what will be the

Question

Solid NH₄HS dissociates into NH₃ and H₂S at a certain temperature, the equilibrium pressure is P atm. If now, NH₃ is pumped into the system so that its partial pressure becomes P atm, what will be the partial pressure (in atm) of H₂S?

Prashant Kotian · Accepted Answer

Correct answer: B. Initially, NH₄HS(s) ⇌ NH₃(g) + H₂S(g). P_NH₃ = P/2, P_H₂S = P/2. K_p = (P/2)(P/2) = P²/4. When NH₃ is added so that new P_NH₃' = P, the new P_H₂S' must satisfy K_p: (P) × (P_H₂S') = P²/4. Thus, P_H₂S' = P/4 = 0.25 P. Therefore, correct answer is B.

💡 Solution & Explanation

Practice 22,000+ questions like this