The process: 2A(g) ⇌ A₂(g) has K_p = 8 × 10⁸ atm⁻¹. If 'A' atoms are taken at 1 atm pressure, what s — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Due to the high K_p, almost all A converts to A₂. Initial P_A = 1 atm. Eq P_A₂ ≈ 0.5 atm. K_p = P_A₂ / P_A² = 8 × 10⁸. 0.5 / P_A² = 8 × 10⁸ => P_A² = 0.5 / (8 × 10⁸) = 1/16 × 10⁻⁸. Taking the square root gives P_A = 0.25 × 10⁻⁴ = 2.5 × 10⁻⁵ atm. Therefore, correct answer is B.