The equilibrium constant for the reaction: H₃BO₃ + glycerin ⇌ (H₃BO₃-glycerin complex) is 0.90. How much glycerin should be added to 1 L of 0.10 M-H₃BO₃ solution, so that 60% of the H₃BO₃ is converted

Question

The equilibrium constant for the reaction: H₃BO₃ + glycerin ⇌ (H₃BO₃-glycerin complex) is 0.90. How much glycerin should be added to 1 L of 0.10 M-H₃BO₃ solution, so that 60% of the H₃BO₃ is converted to boric acid-glycerin complex?

Prashant Kotian · Accepted Answer

Correct answer: B. Initial H₃BO₃ = 0.10 M. 60% reacts = 0.06 M. Eq H₃BO₃ = 0.04 M. Complex formed = 0.06 M. Let initial glycerin be x. Eq glycerin = x - 0.06. K_c = 0.06 / (0.04 × (x - 0.06)) = 0.90. Solving gives 1.5 = 0.90(x - 0.06), so x - 0.06 = 1.667. x = 1.727 M ≈ 1.73 M. Therefore, correct answer is B.

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