When S in the form of S₈ is heated at 900 K, the initial pressure of 1 atm falls by 30% at equilibrium. This is because of conversion of some S₈(g) to S₂(g). The K_p of the reaction is

Question

Prashant Kotian · Accepted Answer

Correct answer: B. The phrase "initial pressure of 1 atm falls by 30%" refers to the partial pressure of S₈ decreasing by 30%. Thus, p_reacted = 0.3 atm. Eq pressure of S₈ = 0.7 atm. The reaction is S₈(g) ⇌ 4S₂(g), so P_S₂ = 4 × 0.3 = 1.2 atm. K_p = (1.2)⁴ / 0.7 = 2.0736 / 0.7 ≈ 2.96 atm³. Therefore, correct answer is B.

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