A quantity of 60 g CH₃COOH and 46 g CH₃CH₂OH reacts in 5 L flask to form 44 g CH₃COOC₂H₅ at equilibr — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

First case: 1 mol acid + 1 mol alcohol → 0.5 mol ester. K_c = (0.5 × 0.5) / (0.5 × 0.5) = 1. Second case: 2 mol acid + 1 mol alcohol. Let x mol ester form. K_c = x² / ((2-x)(1-x)) = 1. Solving gives x² = x² - 3x + 2, so 3x = 2, x = 2/3 mol. Mass of ester = (2/3) × 88 = 58.67 g. Therefore, correct answer is D.