An amount of 3 moles of N₂ and some H₂ is introduced into an evacuated vessel. The reaction starts at t = 0 and equilibrium is attained at t = t₁. The amount of ammonia at t = 2t₁ is found to be 34 g.

Question

An amount of 3 moles of N₂ and some H₂ is introduced into an evacuated vessel. The reaction starts at t = 0 and equilibrium is attained at t = t₁. The amount of ammonia at t = 2t₁ is found to be 34 g. It is observed that w(N₂) / w(H₂) = 14 / 3 at t = t₁/3 and t = t₁/2. The only correct statement is

Prashant Kotian · Accepted Answer

Correct answer: B. The constant mass ratio w(N₂)/w(H₂) = 14/3 before equilibrium implies that their initial masses were exactly in their stoichiometric ratio (28:6 = 14:3). Initial N₂ = 3 moles = 84 g. Thus, initial H₂ = 84 × (3/14) = 18 g. Total initial mass = 84 + 18 = 102 g. By conservation of mass, total mass remains 102 g at any time t. Therefore, correct answer is B.

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