Chemical EquilibriummediumMCQ SINGLE

The equilibrium constant for the reaction: N₂(g) + O₂(g) ⇌ 2NO(g) is 0.09 at 3500 K. The fraction ofChemical Equilibrium Chemistry Question

Question

The equilibrium constant for the reaction: N₂(g) + O₂(g) ⇌ 2NO(g) is 0.09 at 3500 K. The fraction of equimolar mixture of N₂ and O₂ converted into NO is

Answer: A

💡 Solution & Explanation

Let initial moles be 1 each. Eq moles: N₂ = 1-x, O₂ = 1-x, NO = 2x. K = (2x)² / (1-x)² = 0.09. Taking square roots: 2x / (1-x) = 0.3. Thus, 2x = 0.3 - 0.3x, yielding 2.3x = 0.3, and x = 0.3 / 2.3 ≈ 0.13. The converted fraction is 0.13. Therefore, correct answer is A.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry