The equilibrium constant for the reaction: N₂(g) + O₂(g) ⇌ 2NO(g) is 0.09 at 3500 K. The fraction of — Chemical Equilibrium Chemistry Question
Question
The equilibrium constant for the reaction: N₂(g) + O₂(g) ⇌ 2NO(g) is 0.09 at 3500 K. The fraction of equimolar mixture of N₂ and O₂ converted into NO is
Answer: A
💡 Solution & Explanation
Let initial moles be 1 each. Eq moles: N₂ = 1-x, O₂ = 1-x, NO = 2x. K = (2x)² / (1-x)² = 0.09. Taking square roots: 2x / (1-x) = 0.3. Thus, 2x = 0.3 - 0.3x, yielding 2.3x = 0.3, and x = 0.3 / 2.3 ≈ 0.13. The converted fraction is 0.13. Therefore, correct answer is A.
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