For the reaction: X₂(g) + Y₂(g) ⇌ 2XY(g), 2 moles of 'X₂' was taken in a 2 L vessel and 3 moles of 'Y₂' was taken in a 3 L vessel. Both vessels were then connected. At equilibrium, concentration of 'X

Question

For the reaction: X₂(g) + Y₂(g) ⇌ 2XY(g), 2 moles of 'X₂' was taken in a 2 L vessel and 3 moles of 'Y₂' was taken in a 3 L vessel. Both vessels were then connected. At equilibrium, concentration of 'XY' is 0.7 M. Equilibrium concentrations of 'X₂' and 'Y₂' would be

Prashant Kotian · Accepted Answer

Correct answer: D. Total volume = 2 + 3 = 5 L. Initial concentrations: [X₂] = 2/5 = 0.4 M, [Y₂] = 3/5 = 0.6 M. Eq [XY] = 0.7 M. Change in [XY] = 0.7 M, so change in [X₂] = -0.35 M and [Y₂] = -0.35 M. Eq [X₂] = 0.4 - 0.35 = 0.05 M. Eq [Y₂] = 0.6 - 0.35 = 0.25 M. Therefore, correct answer is D.

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