K_p for the reaction: H₂(g) + I₂(s) ⇌ 2HI(g) is 6.4 × 10⁻⁴ atm. On close observation, it is found that the partial pressure of iodine present in vapour state is 1.6 × 10⁻⁴ atm, at the same temperature

Question

K_p for the reaction: H₂(g) + I₂(s) ⇌ 2HI(g) is 6.4 × 10⁻⁴ atm. On close observation, it is found that the partial pressure of iodine present in vapour state is 1.6 × 10⁻⁴ atm, at the same temperature. The K_p for the reaction: H₂(g) + I₂(g) ⇌ 2HI(g) is

Prashant Kotian · Accepted Answer

Correct answer: B. For the first reaction: K_p1 = P_HI² / P_H₂ = 6.4 × 10⁻⁴ atm. The sublimation of iodine gives P_I₂ = 1.6 × 10⁻⁴ atm. For the target reaction involving gaseous iodine, K_p2 = P_HI² / (P_H₂ × P_I₂) = K_p1 / P_I₂ = (6.4 × 10⁻⁴) / (1.6 × 10⁻⁴) = 4. Therefore, correct answer is B.

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