In a system: A(s) β 2B(g) + 3C(g), if the concentration of C at equilibrium is increased by a factor β Chemical Equilibrium Chemistry Question
Question
In a system: A(s) β 2B(g) + 3C(g), if the concentration of C at equilibrium is increased by a factor of 2, it will cause the equilibrium concentration of B to decrease by
Answer: C
π‘ Solution & Explanation
The equilibrium constant is Kc = [B]Β²[C]Β³. Let initial state be [B]βΒ²[C]βΒ³ = Kc. If [C]β = 2[C]β, then [B]βΒ²(2[C]β)Β³ = Kc => [B]βΒ²(8[C]βΒ³) = [B]βΒ²[C]βΒ³. This simplifies to 8[B]βΒ² = [B]βΒ², meaning [B]β = [B]β / β8 = [B]β / (2β2). Therefore, correct answer is C.
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