Iron fillings and water were placed in a 5 L vessel and sealed. The tank was heated to 1000°C. Upon analysis, the tank was found to contain 1.2 g of H₂(g) and 54.0 g of H₂O(g). If the reaction is repr

Question

Iron fillings and water were placed in a 5 L vessel and sealed. The tank was heated to 1000°C. Upon analysis, the tank was found to contain 1.2 g of H₂(g) and 54.0 g of H₂O(g). If the reaction is represented as: 3Fe(s) + 4H₂O(g) ⇌ Fe₃O₄(s) + 4H₂(g), the value of equilibrium constant is

Prashant Kotian · Accepted Answer

Correct answer: D. Moles of H₂ = 1.2 / 2 = 0.6 mol. Moles of H₂O = 54.0 / 18 = 3.0 mol. Both gases occupy the same volume. K_c = [H₂]⁴ / [H₂O]⁴ = (0.6 / 3.0)⁴ = (0.2)⁴ = 0.0016. Therefore, correct answer is D.

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