The equilibrium constant for the mutarotation, α-D-glucose ⇌ β-D-glucose is 1.8. What per cent of th — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Let the % of α-form at equilibrium be x. Then the % of β-form is 100 - x. K = [β] / [α] = (100 - x) / x = 1.8. 100 - x = 1.8x => 2.8x = 100 => x = 100 / 2.8 ≈ 35.71%. Therefore, correct answer is A.