For the reaction: XY₂(g) ⇌ XY(g) + Y(g), the reaction is started with initial pressure of XY₂, 600 m — Chemical Equilibrium Chemistry Question
Question
For the reaction: XY₂(g) ⇌ XY(g) + Y(g), the reaction is started with initial pressure of XY₂, 600 mm Hg. The total pressure for gases at equilibrium is 800 mm Hg. Assuming volume and temperature of the system remains constant, the value of K_p is
Answer: B
💡 Solution & Explanation
Let initial P_XY₂ = 600. Eq P_XY₂ = 600 - p, P_XY = p, P_Y = p. Total P = 600 - p + p + p = 600 + p = 800 mm Hg, so p = 200 mm Hg. Eq pressures: P_XY₂ = 400, P_XY = 200, P_Y = 200. K_p = (P_XY × P_Y) / P_XY₂ = (200 × 200) / 400 = 100 mm Hg. Therefore, correct answer is B.
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