One mole of ethanol is treated with one mole of ethanoic acid at 25°C. One-fourth of the acid change — Chemical Equilibrium Chemistry Question
Question
One mole of ethanol is treated with one mole of ethanoic acid at 25°C. One-fourth of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be
Answer: A
💡 Solution & Explanation
Reaction: Alcohol + Acid ⇌ Ester + Water. Initial moles: 1 each of acid and alcohol. 1/4 of acid reacts = 0.25 mol. Eq moles: Acid = 0.75, Alcohol = 0.75, Ester = 0.25, Water = 0.25. K_c = ([Ester][Water]) / ([Acid][Alcohol]) = (0.25 × 0.25) / (0.75 × 0.75) = 1/9. Therefore, correct answer is A.
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