In a closed tube, HI(g) is heated at 440°C up to establishment of equilibrium. If it dissociates int — Chemical Equilibrium Chemistry Question
Question
In a closed tube, HI(g) is heated at 440°C up to establishment of equilibrium. If it dissociates into H₂(g) and I₂(g) up to 22%, the dissociation constant is
Answer: C
💡 Solution & Explanation
For 2HI ⇌ H₂ + I₂, the degree of dissociation is α = 0.22. K_c = (α/2)² / (1-α)² = (0.11)² / (0.78)² = 0.0121 / 0.6084 = 0.01988 ≈ 0.0199. Therefore, correct answer is C.
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