For the reaction: PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), if initial moles of PCl₅ is 'x', a is the degree of dissociation and P is total pressure at equilibrium, then P_PCl₃ P⁻¹ is equal to

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Prashant Kotian · Accepted Answer

Correct answer: C. Initial moles of PCl₅ = x. Moles at equilibrium: PCl₅ = x(1-a), PCl₃ = xa, Cl₂ = xa. Total moles = x(1+a). The partial pressure of PCl₃ is its mole fraction times total pressure P: P_PCl₃ = [xa / x(1+a)] P = [a / (1+a)] P. Rearranging gives P_PCl₃ P⁻¹ = a / (1+a). Therefore, correct answer is C.

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