For a gaseous equilibrium: 2A(g) ⇌ 2B(g) + C(g), K_p has a value 1.8 at 700 K. The value of K_c for — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

The reverse reaction is 2B(g) + C(g) ⇌ 2A(g), which has K_p' = 1 / K_p = 1 / 1.8. The change in gaseous moles for the reverse reaction is Δn = 2 - 3 = -1. Since K_p' = K_c'(RT)^Δn, K_c' = K_p' / (RT)^-1 = K_p' × (RT) = (1/1.8) × (0.0821 × 700) = 57.47 / 1.8 ≈ 31.9, which is approximately 32. Therefore, correct answer is B.