Chemical EquilibriummediumMCQ SINGLE

The activation energies for the forward and reverse elementary reactions in the system: A ⇌ B, are 1Chemical Equilibrium Chemistry Question

Question

The activation energies for the forward and reverse elementary reactions in the system: A ⇌ B, are 10.303 and 8.000 kcal, respectively, at 500 K. Assuming the pre-exponential factor to be the same for both the forward and reverse steps, the equilibrium constant of the reaction at 500 K is

Answer: D

💡 Solution & Explanation

ΔH = E_a(forward) - E_a(reverse) = 10.303 - 8.000 = +2.303 kcal/mol. Since the pre-exponential factors are equal, K = e^(-ΔH / RT) = e^(-2303 cal / (2 cal/K·mol × 500 K)) = e^(-2303 / 1000) = e^(-2.303) = 10⁻¹ = 0.1. Therefore, correct answer is D.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry