If K₁ and K₂ are the equilibrium constants for a reversible reaction at T₁ K and T₂ K temperature, respectively (T₁

Question

If K₁ and K₂ are the equilibrium constants for a reversible reaction at T₁ K and T₂ K temperature, respectively (T₁ < T₂) and the reaction takes place with neither heat evolution nor absorption, then

Prashant Kotian · Accepted Answer

Correct answer: D. Since there is neither heat evolution nor absorption, ΔH = 0. According to the van 't Hoff equation, ln(K₂/K₁) = (ΔH/R)(1/T₁ - 1/T₂), if ΔH = 0, ln(K₂/K₁) = 0, meaning K₁ = K₂ at all temperatures. Therefore, correct answer is D.

💡 Solution & Explanation

Practice 22,000+ questions like this