The equilibrium mixture for the reaction:<br>2H₂S(g) ⇌ 2H₂(g) + S₂(g) has 1 mole H₂S, 0.20 mole H₂ a — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Equilibrium concentrations are: [H₂S] = 1/2 = 0.5 M, [H₂] = 0.20/2 = 0.1 M, [S₂] = 0.80/2 = 0.4 M. K_c = ([H₂]²[S₂]) / [H₂S]² = (0.1)²(0.4) / (0.5)² = (0.01 × 0.4) / 0.25 = 0.004 / 0.25 = 0.016 M. Therefore, correct answer is C.