For the reaction: I₂(g) ⇌ 2I(g), K_c = 1.0 × 10⁻² mol lit⁻¹. What volume of the vessel should be tak — Chemical Equilibrium Chemistry Question
Question
For the reaction: I₂(g) ⇌ 2I(g), K_c = 1.0 × 10⁻² mol lit⁻¹. What volume of the vessel should be taken so that at equilibrium 1 mole of I₂ and 0.5 mole of 'I' are present at equilibrium?
Answer: A
💡 Solution & Explanation
The equilibrium concentrations are [I₂] = 1/V and [I] = 0.5/V. Substituting into the equilibrium expression: K_c = [I]² / [I₂] = (0.5/V)² / (1/V) = 0.25 / V. Given K_c = 1.0 × 10⁻², 0.01 = 0.25 / V, which yields V = 25 L. Therefore, correct answer is A.
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