The following reaction has an equilibrium constant K_c equal to 3.07 × 10⁻⁴ at 24°C.<br>2NOB(g) ⇌ 2N — Chemical Equilibrium Chemistry Question
Question
The following reaction has an equilibrium constant K_c equal to 3.07 × 10⁻⁴ at 24°C.<br>2NOB(g) ⇌ 2NO(g) + Br₂(g)<br>The correct set of concentrations at which the rate of forward reaction is greater than that of backward reaction is
Answer: C
💡 Solution & Explanation
The forward rate is greater when the reaction quotient Q < K_c. For option (c): Q = ([NO]²[Br₂]) / [NOBr]² = (0.012)²(0.02) / (0.18)² = (1.44 × 10⁻⁴ × 0.02) / 0.0324 = 8.88 × 10⁻⁵. Since 8.88 × 10⁻⁵ < 3.07 × 10⁻⁴, the condition is met. Therefore, correct answer is C.
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