K_p for formation of ethane from hydrogen and ethylene is 5.5 × 10¹⁸ atm⁻¹ and K_p for formation of — Chemical Equilibrium Chemistry Question
Question
K_p for formation of ethane from hydrogen and ethylene is 5.5 × 10¹⁸ atm⁻¹ and K_p for formation of ethylene from hydrogen and acetylene is 5 × 10²⁶ atm⁻¹ at 323 K. What is K_p for the reaction between hydrogen and acetylene to form ethane at 323 K?
Answer: A
💡 Solution & Explanation
Adding the two given reactions yields the target reaction: C₂H₂ + 2H₂ ⇌ C₂H₆. The equilibrium constant for the combined reaction is the product of individual constants: K_p = (5.5 × 10¹⁸) × (5 × 10²⁶) = 27.5 × 10⁴⁴ = 2.75 × 10⁴⁵. Therefore, correct answer is A.
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