XeF₆ + H₂O ⇌ XeOF₄ + 2HF; equilibrium constant = K₁.
XeO₄ + XeF₆ ⇌ XeOF₄ + XeO₃F₂; equilibrium constant = K₂.
Then equilibrium constant for the following reaction will be:
XeO₄ + 2HF ⇌ XeO₃F₂

Question

XeF₆ + H₂O ⇌ XeOF₄ + 2HF; equilibrium constant = K₁.
XeO₄ + XeF₆ ⇌ XeOF₄ + XeO₃F₂; equilibrium constant = K₂.
Then equilibrium constant for the following reaction will be:
XeO₄ + 2HF ⇌ XeO₃F₂ + H₂O

Prashant Kotian · Accepted Answer

Correct answer: C. Subtracting the first reaction from the second yields the target reaction. When reactions are subtracted, their equilibrium constants are divided. Thus, K = K₂ / K₁. Therefore, correct answer is C.

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