Chemical EquilibriummediumMCQ SINGLE

For the reversible reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) at 500°C, the value of K_p is 1.44 × 10⁻⁵ whenChemical Equilibrium Chemistry Question

Question

For the reversible reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) at 500°C, the value of K_p is 1.44 × 10⁻⁵ when partial pressure is measured in atmospheres. The corresponding value of K_c, with concentration in mole litre⁻¹, is

Answer: D

💡 Solution & Explanation

Using the relation K_p = K_c(RT)^Δn. Here, Δn = 2 - 4 = -2. Thus K_p = K_c(RT)⁻², which means K_c = K_p / (RT)⁻². T = 500°C = 773 K. K_c = 1.44 × 10⁻⁵ / (0.082 × 773)⁻². Therefore, correct answer is D.

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