For the reversible reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) at 500°C, the value of K_p is 1.44 × 10⁻⁵ when — Chemical Equilibrium Chemistry Question
Question
For the reversible reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) at 500°C, the value of K_p is 1.44 × 10⁻⁵ when partial pressure is measured in atmospheres. The corresponding value of K_c, with concentration in mole litre⁻¹, is
Answer: D
💡 Solution & Explanation
Using the relation K_p = K_c(RT)^Δn. Here, Δn = 2 - 4 = -2. Thus K_p = K_c(RT)⁻², which means K_c = K_p / (RT)⁻². T = 500°C = 773 K. K_c = 1.44 × 10⁻⁵ / (0.082 × 773)⁻². Therefore, correct answer is D.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes