The equilibrium constant for some reactions are given below against each of the reaction:
(i) 2N₂ + 5O₂ ⇌ 2N₂O₅; K = 5 × 10⁻²⁷
(ii) N₂ + O₂ ⇌ 2NO; K = 2 × 10⁻¹⁵
(iii) N₂ + 2O₂ ⇌ 2NO₂; K = 1.5

Question

The equilibrium constant for some reactions are given below against each of the reaction:
(i) 2N₂ + 5O₂ ⇌ 2N₂O₅; K = 5 × 10⁻²⁷
(ii) N₂ + O₂ ⇌ 2NO; K = 2 × 10⁻¹⁵
(iii) N₂ + 2O₂ ⇌ 2NO₂; K = 1.5 × 10⁻²⁹
Which of the following statement is correct?

Prashant Kotian · Accepted Answer

Correct answer: A,B. The higher the equilibrium constant for formation, the more stable the oxide is relative to its constituent elements. The order of K values is NO (2 × 10⁻¹⁵) > N₂O₅ (5 × 10⁻²⁷) > NO₂ (1.5 × 10⁻²⁹). Thus, NO is the most stable and NO₂ is the least stable oxide. Therefore, correct answer is A,B.

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