For the reaction: CaCO₃(s) ⇌ CaO(s) + CO₂(g); K_p = 2.463 atm at 900 K. The reaction is performed in a rigid vessel of 15.0 l capacity maintained at 900 K, starting with the following amounts of CaCO₃

Question

For the reaction: CaCO₃(s) ⇌ CaO(s) + CO₂(g); K_p = 2.463 atm at 900 K. The reaction is performed in a rigid vessel of 15.0 l capacity maintained at 900 K, starting with the following amounts of CaCO₃(s) (given in Column I). Match the correct information given in Column II for the amount given in Column I.

Prashant Kotian · Accepted Answer

Correct answer: 1-A,C, 2-B,C, 3-B,D. Equilibrium moles of CO₂ = PV/RT = (2.463 × 15) / (0.0821 × 900) = 0.5 mol. This requires 0.5 mol (50 g) of CaCO₃ to dissociate. (1) For 100 g, 50 g dissociates (50%), equilibrium is reached, adding CO₂ shifts backward (A, C). (2) For 50 g, 100% dissociates to just reach equilibrium, adding CO₂ shifts backward (B, C). (3) For 25 g, all 25 g dissociates (100%), but it can't reach equilibrium pressure. Adding more CaCO₃ allows more to form CO₂ (B, D). Therefore, correct answer is 1-A,C, 2-B,C, 3-B,D.

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