The minimum mass (in g) of CaCO₃ required to establish the equilibrium: CaCO₃(s) ⇌ CaO(s) + CO₂(g), — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

To establish equilibrium, the concentration of CO₂ must reach K_c = 0.05 M. In a 1.0 L container, the moles of CO₂ required = 0.05 mol/L × 1.0 L = 0.05 mol. This requires the dissociation of 0.05 mol of CaCO₃. Molar mass of CaCO₃ = 100 g/mol. Minimum mass = 0.05 mol × 100 g/mol = 5 g. Therefore, correct answer is 5.