At 27°C, the rate of forward reaction at time, t, is e⁴ times greater than that of reverse reaction — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

The relationship between the free energy change (ΔG) and the reaction quotient (Q) alongside K is defined by ΔG = RT ln(Q/K). Alternatively, the ratio of the forward rate to the reverse rate is Rate_f / Rate_r = e^(-ΔG / RT). Given Rate_f / Rate_r = e⁴, we have e^(-ΔG / RT) = e⁴. Thus, -ΔG / RT = 4 => ΔG = -4RT. Substituting R ≈ 2 cal/(mol·K) and T = 300 K, ΔG = -4 × 2 × 300 = -2400 cal. The magnitude is 2400. Therefore, correct answer is 2400.