K_p for the reaction: 2NH₃(g) ⇌ N₂(g) + 3H₂(g) at T K is — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

For 2NH₃ ⇌ N₂ + 3H₂, initial NH₃ = 1. Equilibrium moles: NH₃ = 1-α, N₂ = α/2, H₂ = 3α/2. Given α = 2/3 (from previous sub-question), equilibrium moles are NH₃ = 1/3, N₂ = 1/3, H₂ = 1. Total moles = 5/3. Given total pressure P = 50 atm. Partial pressures: P_NH₃ = (1/3 / 5/3) × 50 = 10 atm; P_N₂ = (1/3 / 5/3) × 50 = 10 atm; P_H₂ = (1 / 5/3) × 50 = 30 atm. K_p = (P_N₂) (P_H₂)³ / (P_NH₃)² = (10) × (30)³ / (10)² = 270000 / 100 = 2700 atm². Therefore, correct answer is A.