The equilibrium constant is — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Initially, let moles of alcohol = 1 and acid = 1. At equilibrium, ester = x, water = x, alcohol = 1-x, acid = 1-x. Total moles = 2. Mole fraction of ester = x / 2 = 0.333 (which is 1/3). Thus, x = 2/3. Moles at equilibrium: ester = 2/3, water = 2/3, alcohol = 1/3, acid = 1/3. K_c = ([Ester][Water]) / ([Alcohol][Acid]) = (2/3 × 2/3) / (1/3 × 1/3) = 4 / 1 = 4. Therefore, correct answer is B.