Chemical EquilibriummediumCOMPREHENSIVE

For the reaction, K_c is [Given: (2.463)² = 6.07]Chemical Equilibrium Chemistry Question

Question

For the reaction, K_c is [Given: (2.463)² = 6.07]

Answer: B

💡 Solution & Explanation

The relationship between K_c and K_p is K_p = K_c (RT)^Δn. For this reaction, Δn = 1 - 3 = -2. So K_c = K_p (RT)². We found K_p = 0.16. RT = P_total × V / n_total = (7.5 × 2.463) / 0.3 = 25 × 2.463 = 61.575 L·atm/(mol·K). K_c = 0.16 × (61.575)² ≈ 0.16 × 3791.48 ≈ 606.6 M⁻², which is approximately 607 M⁻². Alternatively using standard R: K_c = 0.16 × (0.0821 × 750)² ≈ 607 M⁻². Therefore, correct answer is B.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry